import os import cpca import re import pandas as pd def get_city_info(text): # 获取当前脚本所在目录的上一级目录 current_dir = os.path.dirname(__file__) parent_dir = os.path.abspath(os.path.join(current_dir, os.pardir)) # 读取区县数据 df_county_addr = os.path.join(parent_dir, 'docs', '区县.xlsx') df_county=pd.read_excel(df_county_addr) # 读取乡镇数据 df_town_addr = os.path.join(parent_dir, 'docs', '乡镇.xlsx') df_town = pd.read_excel(df_town_addr) # 读取市级数据 df_city_addr = os.path.join(parent_dir, 'docs', '市.xlsx') df_city = pd.read_excel(df_city_addr) # 使用cpca库提取地名 df = cpca.transform([text]) province = None city = None district = None if not df.empty: province = df.iloc[0]['省'] city = df.iloc[0]['市'] district = df.iloc[0]['区'] if province is None and city is None and district is None: # 使用正则表达式提取乡镇信息 towns = re.findall(r'[\u4e00-\u9fa5]+镇|[\u4e00-\u9fa5]+乡|[\u4e00-\u9fa5]+街道|[\u4e00-\u9fa5]+庄|[\u4e00-\u9fa5]+营|[\u4e00-\u9fa5]+店', text) if towns: for town in towns: town_name = None if town in df_town['乡镇名称'].values or town in df_town['乡镇简称'].values: town_name = town # 根据乡镇名查找对应的区县代码 town_info = df_town[df_town['乡镇名称'] == town_name].iloc[0] county_code = town_info['区县代码'] # 根据区县代码查找对应的区县名称 county_info = df_county[df_county['区县代码'] == county_code].iloc[0] county_name = county_info['区县名称'] # 将区县名称转换成对应的省份名称 province = county_name # 尝试在市级数据中查找对应的市信息 city_code = county_info['城市代码'] city_info = df_city[df_city['城市代码'] == city_code] if not city_info.empty: city = city_info.iloc[0]['城市名称'] # 将城市名称转换成对应的省份名称 df_city_result = cpca.transform([city]) province = df_city_result.iloc[0]['省'] break# 找到乡镇信息后跳出循环 else: continue return province, city, district if __name__ == '__main__': # 使用方法示例 province, city, district = get_city_info("杞县文化广电新闻出版旅游局") if province==None or city==None or district==None: print("44444") print(province, city, district)